WebFeb 18, 2024 · 0. I think the problem lies here: export default class RequestService extends Component { static contextType = ProviderContext; componentDidMount () { console.log (this.context) } render ()enter code here { return Request Service } } Static declaration means that the variable cannot be used by other classes even if they inherit … WebMay 27, 2024 · 1 Answer. Sorted by: 33. When you assign variables using $: you cannot assign them as part of other variables declared using let, const, or var. When you do assignments using $:, you can only use them in other variables assigned using $:. In the code posted above, you need to change the following lines:
javascript - ReferenceError: Cannot access before initialization ...
WebMay 25, 2024 · 2. You named your variable the same as your function and the compiler is confused: let loginTodayResult = await loginToday (); Share. Follow. answered May 25, 2024 at 14:43. tymeJV. 104k 14 161 157. Add a comment. WebOct 4, 2024 · Try this: import { initializeApp } from 'firebase/app'; const app = initializeApp ( {}); getDatabaseFunc = () => { const db = getDatabase (); const ref = ref (db, "data/") } change the name of the main function to getDatabaseFunc or any other name different from getDatabase () to prevent overriding Share Improve this answer Follow black and gold background hd free
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WebMay 19, 2024 · ReferenceError: Cannot access {variable name} before initialization. I'm aware of "Temporal Deadzones" however this app has had no problem with declaring exports for arrow functions like this, in fact, we declare most/all of our functions in this syntax: export const someFunc = () => {} Now it's only allowing me to export after … WebDec 4, 2024 · This is also the reason for the ReferenceError: Cannot access it before initialization because the program prevents us from accessing the variable before it is … WebOct 21, 2024 · Cannot access 'sub' before initialization It's actually unclear as to what you're trying to do, because logically it looks like you're trying to subscribe to something, but if your subscribed to it, unsubscribe? But you shouldn't do that in the unsubscribe. If you would prefer, you could change your code to the following, dave back to the future